Comment by Robert Wilson III (robert-wilson-iii) on Feynman Paths · 2022-06-20T03:25:40.302Z · LW · GW

They're only syntactically equivalent. Their semantics are completely different. In my opinion, Feynman's semantics is objectively correct regarding the 'literal path' of a particle through spacetime. Given we don't officially know their paths, but we do know their end destinations (wave equation), we can figure all possible paths and have the practically impossible paths cancel each other out: leaving only the probable literal paths of a particle complete with a graph of their trajectories. Schrodinger's equation is far behind semantically. I think Feynman's path integrals are superior.

Comment by Robert Wilson III (robert-wilson-iii) on Feynman Paths · 2022-06-20T03:25:13.294Z · LW · GW

Exactly.