No Anthropic Evidence

If all the coins are quantum-mechanical, you should never quit, nor if all the coins are logical (digits of pi). If the first coin is logical ("what laws of physics are true?", in the LHC dilemma), the following coins are quantum, and your utility is linear in squared amplitude of survival, again you should never quit. However, if your utility is logarithmic in squared amplitude (i.e., dying in half of your remaining branches seems equally bad no matter how many branches you have remaining), then you should quit if your first throw comes up heads.

you only get to 50% probability of dying as the game continues, which is better than the 75% from quitting the game.

20% probability of losing $100 can be better than 10% probability of losing $100 dollars, if the 20% is independent but the 10% is correlated with other events (e.g., if you lose $100 in the 10% of states of the world where you are already poorest). (This is well known in investment theory where being uncorrelated with market risk is valuable for an asset.) Similarly, 50% probability of dying is not necessarily better than 75% probability of dying, if the 50% is correlated with other events (in this case, dying in other quantum branches), and the 75% is independent.

To be more specific, let's analyze the decision problem using UDT. Suppose every copy of you in every branch is facing the same problem, and all of their "original" coins are perfectly correlated (which makes sense since the "original" coin is supposed to be a stand-in for "the laws of physics are such that LHC would destroy Earth if some accident didn't intervene"). You're trying to choose between the strategies (A) "keep flipping until the game ends" and (B) "keep flipping until either the game ends or I get to 1000 heads, then quit".

• Consequences of A: 50% chance nobody survives, 50% chance nobody dies.
• Consequences of B: 50% chance 1/4 2^-1000 of your copies survive, 50% chance 3/4 2^-1000 of your copies die.

A UDT agent might choose B over A because saving 1/4 * 2^-1000 of its copies is considered more valuable in the state where there are already very few copies of itself. Perhaps our intuitions for "anthropic evidence" should be translated into such preferences, in line with my previous suggestions?

(My answer is very similar to Benja's. I'm guessing that our perspective is not the easiest to understand, and it helps to have multiple explanations.)

There are 2^1001 equally likely (in the prior) scenarios, by combinations of coin flips. Applying evidence, anthropic or otherwise, means eliminating possibilities which have been excluded by the evidence and renormalising what's left. Doing this leaves two equally likely scenarios, that the original coin was tails and the other 1000 flips were heads, or that all 1001 flips were heads. The chances of the original coin being heads are therefore, still, 50-50. Keep flipping.

If this is meant to highlight some of the horribly flawed thinking that comes with anthropic evidence then you've done an excellent job. You've imposed an assymetry between "dieing" and "surviving the game and moving on", but no such assymetry exists. Both possibilities would equally prevent you from being in the situation you describe.

Why would you ever keep playing? You don't get anything for staying in the game, only an additional chance of getting shot.

I am missing something. The total probability of being shot while playing is never more than 50%, why would you ever quit?

I think you're wrong. Suppose 1,000,000 people play this game. Each of them flips the coin 1000 times. We would expect about 500,000 to survive, and all of them would have flipped heads initially. Therefore, P(I flipped heads initially | I haven't died yet after flipping 1000 coins) ~= 1.

This is actually quite similar to the Sleeping Beauty problem. You have a higher chance of surviving (analogous to waking up more times) if the original coin was heads. So, just as the fact that you woke up is evidence that you were scheduled to wake up more times in the Sleeping Beauty problem, the fact that you survive is evidence that you were "scheduled to survive" more in this problem.

On the other hand, each "heads" you observe doesn't distinguish the hypothetical where the original coin was "heads" from one where it was "tails".

This is the same incorrect logic that leads people to say that you "don't learn anything" between falling asleep and waking up in the Sleeping Beauty problem.

I believe the only coherent definition of Bayesian probability in anthropic problems is that P(H | O) = the proportion of observers who have observed O, in a very large universe (where the experiment will be repeated many times), for whom H is true. This definition naturally leads to both 2/3 probability in the Sleeping Beauty problem and "anthropic evidence" in this problem. It is also implied by the many-worlds interpretation in the case of quantum coins, since then all those observers really do exist.

"Intuitively, it seems as if 1000 "heads" is "anthropic evidence" for the original coin being "tails", that the long sequence of "heads" can only be explained by the fact that "tails" would have killed you."

Can someone explain why this is? My intuitive answer wasn't the above, because I'd already internalized that, under uncertainty, it's a fair coin with no future reaching bias. My intuitive feeling was that I'm likely playing against a biased-towards-heads coin. No more, no less, and at most a little information that the original flip possibly came up heads rather than tails.

Let's took at the different possible assumptions.

If you assume a unique classical universe with one-way causality, then obviously, the fact you only throw heads is just luck, it doesn't say anything about the initial throw. You could promote hypothesis like "the coin is biased, because the ones running that experiment are sadistic who like to see my fear every time the coin is tossed", and maybe from that you could change your estimate of the first coin being biased, depending of your understanding of human psychology.

If you assume MWI it gets more complicated, and depends if the coin tossing is "quantum-random" or not. A usual coin tossing is not "quantum-random", the reasons behind the coin ending heads or tails are in classical physics, well above the level of "quantum noise". So in all the existing worlds (or a very, very large majority of them), the toss will give the same results, so you're back to the first case.

If you assume MWI and the coin toss are "quantum random", then after two tosses (not counting the initial), you've 8 outcomes : HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. You can only experience H and THH. On the 8 copies of you, 3 will be dead, 5 alive. But for there are two copies seeing HH, you can't tell apart THH and HHH, both have p=1/2. p(HH | I'm alive) = 2/5, but p(T | *HH and I'm alive) is still 1/2.

Now, if you assume the first coin was not quantum, but the subsequent are ... there is no longer 8 worlds having the same Born probabilities (the same "level of existence") but only two sets of 4 worlds, each set having a 1/2 probability of existing. In one set of world, there will be just one copy of you seeing "HH", on the other, there will be 4 copies of you seeing all the possible outcomes.

Then we can rephrase the problem in a way that doesn't involve the anthropic principle, making it a more classical problems of probabilities. We take 5 similar pieces of paper. Two are written HH, the others HT, TH and TT. One HH is put aside, then each are folded. Then someone tosses a coin. If it's tails, you are given the lone HH paper. If it's heads, you're giving one at random among the 4 papers. You open your paper, and it's HH. What's the probability the coin landed tails ? Well, it's 4/5, not 1/2.

So, my answer is : if MWI holds, and the first coin is not quantum random, but the later are quantum random, you should consider the 1000 heads (and even stop much before) to be strong evidence towards "the initial was tails". If none or all of the coins are quantum random, or you don't believe in MWI, you shouldn't.

I am confused.

I think, depending on how unlikely a world with anybody finding such an unlikely chain of throws is, and how his/her priors look, the gambler might want to update to almost certainty on quantum realism or one of the tegmarks; ie. the fundamental improbability of a finite world containing this outcome implies that reality is such that such an observation can be expected.

At least if I'm not completely confused. Wait, is that what the "unloaded gun" was supposed to emulate? But then it comes down to whether you're optimizing over total universes or surviving universes - if you don't care about the branches where you die, the game is neutral to you (if you're certain you're in a quantum realism universe) - you can play, you can leave, it makes no difference. The probability number would be irrelevant to your decisionmaking. I suppose this is one reason we should expect quantum immortality as a philosophy to weed itself out of the observable universe.

If you look back at 1000 heads in a quantum immortality mode where you ignore dead branches, you have an anticipation of 0.5 (initial throw) of observing that series in the loaded universe, but only 0.5/2^1000 in the unloaded universe, so the strategy "after turn 1000, if you got 1000 heads, assume you're in the loaded half" will succeed in 0.5/total anticipated cases and fail in (0.5/2^1000)/total anticipated cases. But then again, in a quantum immortality mode, the entire game is irrelevant and you can quit or play however you like. So this is somewhat confusing to me. Excuse me for rambling.

Anthropic evidence depends on the reference class you put yourself into, which in this case has a very definite meaning: "What kind of other person would be faced with the same problem you are?"

If you play the game for up to 1000 rounds, then with probability 1/2 - 1/2^1000 you got a T at some point and survived anyway (we call this a Type 1 outcome). Otherwise, you are probably dead, but with probability 1/2^999, you saw a run of 1000 heads (a Type 2 outcome).

It's true that Pr[gun is loaded | you survived] is close to 0. In fact, if you didn't see the coin flips then this is the probability you should use: given that you survived 1000 coin flips, you are better off continuing the game, because the gun most likely isn't loaded.

But once you get shown the coin flips, then the decisions you can make are different. In a Type 1 outcome, you know the gun isn't loaded, because it's been triggered and didn't kill you (Edit: so this means you're free to leave anyway). So when we decide "what should we do if the coin came up "heads" 1000 times?" we should only be looking at the Type 2 outcomes, because that's the only situation in which we need to make that decision.

And the Type 2 outcome happens with equal probability whether or not the gun was loaded. Therefore you should expect the gun to be loaded with 50% probability, and keep playing.