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comment by Phil · 2021-01-31T22:12:38.271Z · LW(p) · GW(p)

The logic would be correct if, when Yovanni lied, he would always say it was Xavier Williams.  In that case, there would be (roughly) 1/100 "Yovanni lies and says it was Xavier" for every 1/1,000,000 "Yovanni tells the truth and says it was Xavier."

But if Yovanni lies randomly, and you have no prior that he would lie and say Xavier any more than he would lie and say anyone else, you have 1/100 * 1/1,000,000 "Yovanni lies and also Yovanni says it was Xavier" for every 99/100  * 1/1,000,000 "Yovanni tells the truth and says it was Xavier," which is 99% truth.

Replies from: anon-user
comment by Anon User (anon-user) · 2021-02-01T17:59:22.828Z · LW(p) · GW(p)

Right, which is why the claim is immediately more suspect if Xavier is a close friend/relative/etc.

comment by Unnamed · 2021-02-01T05:15:13.367Z · LW(p) · GW(p)

Crazy story: one time I went to random.org and generated a 20 digit string and it was 89921983981118509034.

comment by Vladimir_Nesov · 2021-02-01T08:08:40.278Z · LW(p) · GW(p)

Let's apply Bayes formula in odds form [LW(p) · GW(p)] to this example. Let = "Xavier won the lottery", , = "Yovanni says Xavier won the lottery". We have (for simplicity, let's assume that Xavier couldn't be someone who didn't even enter the lottery), . What is ? Given that someone other than Xavier won the lottery, what is the probability that Yovanni would claim that it was Xavier in particular who did? While Yovanni might have a reason to single out Xavier, Zenia doesn't, so from the hypothesis they would predict that anyone could be wrongly named the winner, which gives picking Xavier one in a million chance (also, the Yovanni within the hypothesis won't pay attention to in particular, so can't anchor to Xavier based on that). Then, Yovanni must make a mistake or decide to lie, with probability of, say, 1%. In total, we have . Putting this in the formula, we get , so Xavier is probably the winner after all.

(This is the same as Phil's answer [LW(p) · GW(p)], formulated a little bit differently.)

comment by Ericf · 2021-02-01T02:03:21.684Z · LW(p) · GW(p)

Phil is right, and also "don't believe him" is a mapping of "the thing he said is x% likely" onto a single believe/don't with a cutoff at t%. So it can be true that both A) you update to believe it is more than 1/1,000,000 that Xavier won, but also B) your level still falls below t%, so you don't believe it.

As I've noted before, this is actually how real people behave. They know the odds of winning are super low, so when they get a bit of evidence that says "I won" they seek out independent bits of evidence (eg, asking a second person to look at the ticket and confirm the numbers; checking their bank account after putting in the claim to confirm the balance was updated) before acting on the reality of winning.

comment by Joachim Bartosik (joachim-bartosik) · 2021-02-02T10:40:14.335Z · LW(p) · GW(p)

The description doesn't fully specify what's happening.

  1. Yovanni is answering questions in form of "Did X win the lottery". And gives correct answer 99% of the time. In that case you shouldn't believe that Xavier won the lottery. If you asked the question for all the participants you'd end up with list of (in expectation) about 10'000 people for which Yovanni claimed they won the lottery.
  2. Yovanni is making 1 claim about who won the lottery. And for questions like that Yovanni gives correct answers 99% of the time. In that case Phil got it and probability that Xavier won is 99%.

 

Also I think it's better to avoid using humans in examples like that and try to use something else / not agenty. Because humans can strategically lie (for example somebody can reach very high accuracy in statements they make by talking a lot about simple arithmetic operations. If they later say you should give them money and will receive 10x as much in return then you shouldn't conclude that there is 99+% chance this will work out and you should give them a lot of money).

comment by Shmi (shminux) · 2021-02-01T07:58:01.091Z · LW(p) · GW(p)

Yovanni tells Zenia, "The winner of the lottery was Xavier Williams of California."

When evaluating the veracity of this statement, Zenia is not evaluating the odds of someone with that name winning a lottery. Someone won the lottery and their name has been made publicly available. What she is evaluating is Yovanni's general trustworthiness in this kind of situations. Does Yovanni like to make stuff up? To play pranks? Has reading comprehension issues? The odds of the lottery have zero to do with this. They would only matter if Yovanni could have some useful additional information, such as if it was a raffle at a party, and you knew that no one named Xavier Williams was invited.

Replies from: aphyer
comment by aphyer · 2021-02-01T14:02:17.725Z · LW(p) · GW(p)

Scenario 1: A friend who you know to generally be fairly trustworthy tells you that there is a snowstorm in New York City.  

Scenario 2: A friend who you know to generally be fairly trustworthy tells you that there is a snowstorm in Ecuador.  

Scenario 3: A friend who you know to generally be fairly trustworthy tells you that there is a snowstorm on the surface of Venus, which they spotted by looking up into the sky with their keen vision after Batman showed up and used his power ring to grant them super senses.

 

As I understand your comment above, it sounds like you're saying you will evaluate the veracity of the three scenarios above the same way, caring only about the friend's trustworthiness and not at all about how implausible the story sounds.  This seems very strange - am I misunderstanding?

The 'paradox' being mentioned in the post is that Xavier Williams winning the lottery seems like it should be a plausible-sounding story (a la Scenario A), but a naive mathematical analysis (missing Phil's point above) makes it seem like a very implausible-sounding one.

Replies from: shminux
comment by Shmi (shminux) · 2021-02-01T21:05:43.287Z · LW(p) · GW(p)

No, these are completely different. NYC and Equador are not random samples of places where a snowstorm is equally likely. A more charitable comparison would be "It's winter in the Northern Hemisphere, and there was a snowstorm in one of the major cities. Yovanni checks the weather app and says that it's in NYC."

comment by Dagon · 2021-02-01T04:15:09.779Z · LW(p) · GW(p)

If you're one in a million, there are 9 of you in Manhattan, and 1400 of you in China.

Replies from: Viliam
comment by Viliam · 2021-02-04T22:03:43.318Z · LW(p) · GW(p)

Also 200 in Nigeria. One of them won the lottery but is too poor to pay the related tax, so he is willing to share the winnings with you 50:50 if you help him pay the tax first.

comment by cousin_it · 2021-02-01T11:45:27.796Z · LW(p) · GW(p)